Build the Circuit for F = (A+B)(C+D)(E+F) Under a Two-Input Gate Constraint
Standard cell libraries restrict gate fan-in to guarantee predictable timing and layout area. Complex Boolean equations must often be mapped to a cascade of simpler two-input primitives.
The circuit must evaluate the Product of Sums (POS) expression: Y = (A + B) * (C + D) * (E + F). The output is labeled Y to avoid confusion with the input F. The circuit evaluates to 1 only when at least one input in every pair is 1.
| A | B | C | D | E | F | Y | |-----|-----|-----|-----|-----|-----|-----| | 0 | 0 | 0 | 0 | 0 | 0 | 0 | | 1 | 0 | 1 | 0 | 1 | 0 | 1 | | 1 | 1 | 0 | 0 | 1 | 1 | 0 | | 1 | 1 | 1 | 1 | 1 | 1 | 1 |
Constraints
- Use only two-input logic gates.
- Combinational logic only.
Topics
Solve this problem
Place the gates, wire them up and watch the signals settle. Every submission runs on the same simulation engine that grades it.
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